Fetchall return json
WebSep 20, 2024 · This result is not usable for me, as I need a JSON which needs to have the structure shown here: http://stats.valonic.com/server_processing.php Here I used the … WebDec 22, 2024 · A good database adapter implementation will fetch rows in batches from the server, saving on the memory footprint required as it will not need to hold the full result set in memory. cursor.fetchall () has to return the full list instead.
Fetchall return json
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WebJul 17, 2024 · Сделаем функцию, достающую и добавляющую информацию по домам в базу, попутно будем записывать все json-ошибки (скорее всего, в ответе не было json) и неизвестные ошибки (скорее всего, ответа ... WebBy default, FastAPI would automatically convert that return value to JSON using the jsonable_encoder explained in JSON Compatible Encoder. Then, behind the scenes, it would put that JSON-compatible data (e.g. a dict) inside of a JSONResponse that would be used to send the response to the client.
WebJul 28, 2016 · The problem you are encountering happens because you only turn the fetched items into dicts, without their description. dict in python expects either another dict, or an iterable returning two-item tuples, where for each tuple the first item will be the key, and the second the value.. Since you only fetch two columns, you get the first one … WebApr 17, 2014 · Sorted by: 1. Your code only returns the values. To also get the column names you need to query a table called 'sqlite_master', which has the sql string that was used to create the table. c.execute ("SELECT sql FROM sqlite_master WHERE " \ "tbl_name='your_table_name' AND type = 'table'") create_table_string = cursor.fetchall …
WebWhen used in write mode, calling fetchall will position the record pointer at the last case of the active dataset, or if there are splits, the last case of the current split. Cases from the … WebJan 5, 2024 · In your original code, you didn't return the variable json_output; To fetch only one result, use fetchone instead fetchall; After cursor.close () got called, you can obtain nothing from that cursor no matter you fetched before or not; Use try-finally to ensure that cursor always get closed (at last). Here's the fixed code:
WebIf you want to return another JSON type, use the jsonify () function, which creates a response object with the given data serialized to JSON. from flask import jsonify @app.route("/users") def user_list(): users = User.query.order_by(User.name).all() return jsonify( [u.to_json() for u in users])
WebDec 24, 2024 · The question doesn't specify your SQL adapter, but if you're using SQLAlchemy with Flask, here's an example of how to query a database and output the result in your desired format: from flask import Flask from models import db import json app = Flask (__name__) app.config ['SQLALCHEMY_DATABASE_URI'] = … fine hair boysWebOct 4, 2024 · It has single quotes while JSON strings should have double quotes to be valid. You don't really have the option to mass replace the quotation marks from the database so use json.dumps before loading the JSON to convert the quotation marks. Try this: detailsdict[obj]=json.loads(json.dumps(record['details'])) Or use ast.literal_eval: fine hair breakageWebNov 1, 2024 · Add a comment. 1. you can use sqlalchemy cursor and cursor's description. def rows_as_dicts (cursor): """convert tuple result to dict with cursor""" col_names = [i [0] for i in cursor.description] return [dict (zip (col_names, row)) for row in cursor] db = SQLAlchemy (app) # get cursor cursor = db.session.execute (sql).cursor # tuple result to ... fine hair braidsWebHow is the better way to do a "fetchall" to statement in java, for convert after in a json response? I have a sql query, works fine, but I want to show a JSON response, with the … ernst thomas hemerWebJun 22, 2024 · 12. To return $data in json format using Drupal-7's page callback output, you should return through : drupal_json_output ($data); in your page callback function. For more ref : http://api.drupal.org/api/drupal/includes!common.inc/function/drupal_json_output/7. fine hair brushWebNov 4, 2014 · def cont (request): try: get = cursor.execute ('SELECT id, number FROM tblContract') qs = get.fetchall () data = [] for obj in qs: item = { 'id': obj.id, 'number': obj.number } data.append (item) return JsonResponse ( {'data': data}) except: return JsonResponse ( {'data': 'errorrr'}) finally: con.close Share Improve this answer Follow ernst thomas oldenburgWeb我正在嘗試通過PHP將來自Mysql數據庫的數據編碼為JSON格式,這是代碼段: 但是我無法將此數組編碼為JSON。 print r rows 打印以下內容: 然后echo json encode response 打印以下內容: adsbygoogle window.adsbygoogle .pu ernst thomas gmbh hemer